Hardy-Weinberg Made Easy: A Seventh Way
Jack Doepke
Teacher Instructions
Target Age: High School (9-12) Student/Class time required:
40 minutes
The purpose of this lesson is to slowly introduce the Hardy-Weinberg
Law and population genetics to your students after you have completed
Mendelian genetics. Using this format, you ease the students into
the concept by relying on the knowledge they already have.
Read the following to your students or write it out on the board
or overhead.
Yogi Bear decided one year that for future conservation plans
regarding the usage of the park and its equipment, it would be
important for him to gather some data about the bears that inhabit
the park, so he petitioned the use of some of the other animals
in the park and sent them out to gather some data. A week later
the survey was completed and tabulated. It showed that 360 brown
bears and 640 black bears resided in the park. The data also showed
that the bears mated regardless of color, but that when brown
bears mated with brown bears only brown cubs were produced, but
when black bears mated with other black bears sometimes brown
cubs were produced. Yogi also noticed that there did not appear
to be any obvious survival value to having one color or the other.
The first question that Yogi wanted answered was which trait,
black or brown, is dominant and which is recessive. Can you help
Yogi figure this out with the information provided?
Hint: To determine the answer set up a cross using all possible
combinations of coat colors and look at the expected results.
The answer will become obvious.
In making plans for purchasing new band uniforms for the Fourth
of July parade, Yogi thought it would be nice if the brown bears
and black bears had different color ties so he next wanted to
know if the percent of bears having brown coat color would be
the same for the next generation. So he called upon the wise old
owl, Doc Cronkite, for he was the wisest of all the animals in
the forest.
'Doc,' he asked, 'using the information that
I gathered in my survey, can I determine if the coat colors of
the bears here in Jellystone will be the same in future generations
to come?'
'Yes, Yogi, thanks to two very smart men by the names
of Hardy and Weinberg, I think we can extract that information
for you from your survey. But first we have to go back and look
at our old friend the Punnett square from our studies in Mendelian
genetics. We are going to modify the way we use the square slightly
to suit our purposes. First of all, instead of thinking in terms
of a single cross between two mating individuals, we are going
to think in terms of the whole population of bears.
'First we will change this model slightly to fit our data:'
'Now remember to put the male gametes across the top and
the female gametes down the side:'

'We will put all the gametes on the top coming from all
of the males and we will put all the gametes from the females
down the side. We will calculate these by working backwards or
from what we can deduce from what we know about what is inside
the box.'
First help Yogi to calculate the percent of gametes coming
from the male and female population that was required to produce
360 brown bears. Hint: First think in terms of percent rather
than 360 bears.

Now notice that some number B (male gametes) must have been multiplied
by some number 2 (female gametes) to produce our 36% of brown
bears. Help Yogi to calculate that number.

Notice that the frequency of the recessive gene for all of the
360 brown bears (36%) has to be .6 (60%) for both the male and
female population. We refer to this as the gene frequency for
the recessive gene and we assign the letter q to it. Now to calculate
the frequency of the dominant gene in the population we simply
subtract from 1 (100%). Thus p + q = 1. This gives us a value
of .4 (40%) for the dominant gene.

From this we can see that :
- p2 = (.4x.4) .16 or 16%
- 2pq = (2 x .4 x .6 ) .42 or 42%
-
q2 = (.6 x.6 ) .36 or 36%
p2 + 2pq + q2 = 1 is the other part of the Hardy-Weinberg Equation
that represents the genetic percentages of the offspring. Do
not confuse this with the gene frequency in the population or
gene pool.
Tired and hungry from all of this math, Yogi and Doc took a break
and walked down by the pool and had some cookies and milk. This
was relaxing and fun for Yogi, but all Doc wanted to do was count
the number of chocolate chips in the cookies. Yogi guessed that
Doc must have inherited a mathematical gene from a parent. Probably
his mother. Rested ,they began anew.
'Doc, I'm ready to tackle my next question, if
you are. How do I tell if the next generation of my bears will
be the same color?'
'Of course they will be the same color, Yogi. What you
want to know is, will they be in the same genetic ratio as before.'
'Yeah, that's what I meant.'
'For that, Yogi, we have to ask ourselves, what kind of
gametes can the bears that we have now produce and in what proportion?'
'How do we do that, Doc?'
'Well, you remember from your study of meiosis, don't
you, that each parent carries two genes or alleles for a trait,
but they only contribute one to their offspring.'
'Sure I remember that, Doc. That is pretty obvious, otherwise
our chromosome number wouldn't stay constant from one generation
to the next.'
'That's right, Yogi, but do you remember which
controls what gene goes into a gamete?'
'Does it have something to do with dominance and recessiveness?'
'No, Yogi, it is strictly a matter of chance.'
'Oh! So our job should be easy then. We just need to go
back to our original percentages and work from there.'
Can you help Yogi do this?
16% BB + 42% Bb + 36% bb = 100%
16% BB can produce what kind of gametes_________________________
42% Bb can produce what two kind of gametes _________ + _________
36% bb can produce what kind of gametes _________________________
Results:
- .16 B +.24 B/.40 B
- .24 b +.36 b/ .60 b

From this we can see that if we fill in the Punnett square our
percentages for this new generation will be exactly the same as
the present generation. This is a fundamental principle of the
Hardy-Weinberg Equation.
Gene frequencies will remain constant from one generation to
the next in a population not undergoing natural selection.
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